What is the foci y^2-4x^2+16x-2y=31 ?

The foci y^2-4x^2+16x-2y=31 is (2,1+2sqrt(5)),(2,1-2sqrt(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y^2-4x^2+16x-2y=31

foci

y^{2} - 4 x^{2} + 16 x - 2 y = 31

(2, 1 + 25), (2, 1 - 25)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

y^{2} - 4 x^{2} + 16 x - 2 y = 31 :

Up-down Hyperbola with

(h, k) = (2, 1), a = 4, b = 2

(2, 1 + c), (2, 1 - c)

Compute

c :

c = 4^{2} + 2^{2} : 25

(2, 1 + 25), (2, 1 - 25)

\frac{y ^{2}}{12.00 6 ^{2}} - \frac{x ^{2}}{2.00 1 ^{2}} = 1

\frac{x ^{2}}{81} - \frac{y ^{2}}{49} = 1

\frac{( x + 3 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{16} = 1

x^{2} - y^{2} = - 4

- 4 x^{2} + y^{2} - 16 x - 52 = 0

What is the foci y^2-4x^2+16x-2y=31 ?
The foci y^2-4x^2+16x-2y=31 is (2,1+2sqrt(5)),(2,1-2sqrt(5))