What is the foci (y^2)/(12.006^2)-(x^2)/(2.001^2)=1 ?

The foci (y^2)/(12.006^2)-(x^2)/(2.001^2)=1 is (0,12.17160…),(0,-12.17160…)

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foci (y^2)/(12.006^2)-(x^2)/(2.001^2)=1

foci

\frac{y ^{2}}{12.00 6 ^{2}} - \frac{x ^{2}}{2.00 1 ^{2}} = 1

(0, 12.17160 \dots), (0, - 12.17160 \dots)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{12.00 6 ^{2}} - \frac{x ^{2}}{2.00 1 ^{2}} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 12.006, b = 2.001

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 12.00 6^{2} + 2.00 1^{2} : 12.17160 \dots

(0, 0 + 12.17160 \dots), (0, 0 - 12.17160 \dots)

Refine

(0, 12.17160 \dots), (0, - 12.17160 \dots)

\frac{x ^{2}}{81} - \frac{y ^{2}}{49} = 1

\frac{( x + 3 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{16} = 1

x^{2} - y^{2} = - 4

- 4 x^{2} + y^{2} - 16 x - 52 = 0

\frac{y ^{2}}{9} - \frac{x ^{2}}{1} = 1

What is the foci (y^2)/(12.006^2)-(x^2)/(2.001^2)=1 ?
The foci (y^2)/(12.006^2)-(x^2)/(2.001^2)=1 is (0,12.17160…),(0,-12.17160…)