What is the foci (y^2)/3-(x^2)/3 =1 ?

The foci (y^2)/3-(x^2)/3 =1 is (0,sqrt(6)),(0,-sqrt(6))

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foci (y^2)/3-(x^2)/3 =1

foci

\frac{y ^{2}}{3} - \frac{x ^{2}}{3} = 1

(0, 6), (0, - 6)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{3} - \frac{x ^{2}}{3} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 3, b = 3

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 3^{2} + 3^{2} : 6

(0, 0 + 6), (0, 0 - 6)

Refine

(0, 6), (0, - 6)

y^{2} - x^{2} = \frac{4}{25}

\frac{( y + 3 ) ^{2}}{10} - \frac{( x - 3 ) ^{2}}{20} = 1

\frac{x ^{2}}{64} - \frac{y ^{2}}{- 39} = 1

- \frac{x ^{2}}{144} + \frac{y ^{2}}{25} = 1

1 - \frac{x ^{2}}{4} + (y - 1)^{2} = 0

What is the foci (y^2)/3-(x^2)/3 =1 ?
The foci (y^2)/3-(x^2)/3 =1 is (0,sqrt(6)),(0,-sqrt(6))