What is the foci-(x^2)/(144)+(y^2)/(25)=1 ?

The foci-(x^2)/(144)+(y^2)/(25)=1 is (0,13),(0,-13)

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foci-(x^2)/(144)+(y^2)/(25)=1

foci

- \frac{x ^{2}}{144} + \frac{y ^{2}}{25} = 1

(0, 13), (0, - 13)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

- \frac{x ^{2}}{144} + \frac{y ^{2}}{25} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 12

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} + 1 2^{2} : 13

(0, 0 + 13), (0, 0 - 13)

Refine

(0, 13), (0, - 13)

1 - \frac{x ^{2}}{4} + (y - 1)^{2} = 0

x^{2} - y^{2} = 4 x

y^{2} - x^{2} = 1

(y + 4)^{2} - \frac{( x - 2 ) ^{2}}{4} = 1

\frac{( x - 6 ) ^{2}}{8} - \frac{( y - 5 ) ^{2}}{1} = 1

What is the foci-(x^2)/(144)+(y^2)/(25)=1 ?
The foci-(x^2)/(144)+(y^2)/(25)=1 is (0,13),(0,-13)