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Popular >

foci 2x^2+7y^2=14

Solution

foci

2 x^{2} + 7 y^{2} = 14

Solution

(5, 0), (- 5, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

2 x^{2} + 7 y^{2} = 14 :

Ellipse with center

(h, k) = (0, 0), a = 7, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 7^{2} - 2^{2} : 5

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

Popular Examples

49 y^{2} - x^{2} = 49

foci 9x^2+25y^2=225 foci

9 x^{2} + 25 y^{2} = 225

(y^2)/9-(x^2)/(16)=1

\frac{y ^{2}}{9} - \frac{x ^{2}}{16} = 1

vertices f(x)=-x^2-4x-3 vertices

f (x) = - x^{2} - 4 x - 3

x^{2} + y^{2} - 16 = 0

Frequently Asked Questions (FAQ)

What is the foci 2x^2+7y^2=14 ?
The foci 2x^2+7y^2=14 is (sqrt(5),0),(-sqrt(5),0)