What is x^2+y^2-6x+4y+9=0 ?

The solution to x^2+y^2-6x+4y+9=0 is Circle with (a,b)=(3,-2),r=2

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x^2+y^2-6x+4y+9=0

x^{2} + y^{2} - 6 x + 4 y + 9 = 0

(a, b) = (3, - 2), r = 2

Solution steps

x^{2} + y^{2} - 6 x + 4 y + 9 = 0

Rewrite

x^{2} + y^{2} - 6 x + 4 y + 9 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 2))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (3, - 2), r = 2

f (x) = x^{2} - 4 x + 3

\frac{( x - h ) ^{2}}{a ^{2}} + \frac{( y - k ) ^{2}}{b ^{2}} = 1

x^{2} + y^{2} + 4 x - 6 y - 3 = 0

\frac{x ^{2}}{25} - \frac{y ^{2}}{4} = 1

9 x^{2} + 16 y^{2} = 144

What is x^2+y^2-6x+4y+9=0 ?
The solution to x^2+y^2-6x+4y+9=0 is Circle with (a,b)=(3,-2),r=2