What is (-k(x)}{3x^2}=\frac{-6)/5 ?

The solution to (-k(x)}{3x^2}=\frac{-6)/5 is Parabola with (h,k)=(0,0),p= 5/72

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(-k(x)}{3x^2}=\frac{-6)/5

\frac{- k ( x )}{3 x ^{2}} = \frac{- 6}{5}

(h, k) = (0, 0), p = \frac{5}{72}

Solution steps

\frac{- y}{3 x ^{2}} = \frac{- 6}{5}

Rewrite

\frac{- y}{3 x ^{2}} - \frac{- 6}{5} = 0

in the standard form

4 \cdot \frac{5}{72} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{5}{72}

(y - 1)^{2} = 8 (x + 2)

- 6 y^{2} + 4 y = x + 3 y - 2

5 y^{2} - z - 6 = 0

x^{2} - 12 x - 4 y + 20 = 0

x^{2} - 8 x - 4 y = 0

What is (-k(x)}{3x^2}=\frac{-6)/5 ?
The solution to (-k(x)}{3x^2}=\frac{-6)/5 is Parabola with (h,k)=(0,0),p= 5/72