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Popular >

foci y^2-y-x+1=0

Solution

foci

y^{2} - y - x + 1 = 0

Solution

(1, \frac{1}{2})

Solution steps

Rewrite

y^{2} - y - x + 1 = 0

in the standard form

4 \cdot \frac{1}{4} (x - \frac{3}{4}) = (y - \frac{1}{2})^{2}

(h, k) = (\frac{3}{4}, \frac{1}{2}), p = \frac{1}{4}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(\frac{3}{4}, \frac{1}{2})

along the x-axis

(\frac{3}{4} + p, \frac{1}{2})

= (\frac{3}{4} + \frac{1}{4}, \frac{1}{2})

Refine

(1, \frac{1}{2})

Popular Examples

9 y^{2} - 16 x^{2} = 81

9x^2-4y^2-54x-8y+113=0

9 x^{2} - 4 y^{2} - 54 x - 8 y + 113 = 0

vertices y^2+2y+x=0 vertices

y^{2} + 2 y + x = 0

x^2+y^2+8x-2y-19=0

x^{2} + y^{2} + 8 x - 2 y - 19 = 0

foci (x^2}{36}+\frac{y^2)/4 =1 foci

\frac{x ^{2}}{36} + \frac{y ^{2}}{4} = 1

Frequently Asked Questions (FAQ)

What is the foci y^2-y-x+1=0 ?
The foci y^2-y-x+1=0 is (1, 1/2)