What is (x^2)/(36)+(y^2)/(25)=1 ?

The solution to (x^2)/(36)+(y^2)/(25)=1 is Ellipse with (h,k)=(0,0),a=6,b=5

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(x^2)/(36)+(y^2)/(25)=1

\frac{x ^{2}}{36} + \frac{y ^{2}}{25} = 1

(h, k) = (0, 0), a = 6, b = 5

Solution steps

\frac{x ^{2}}{36} + \frac{y ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{36} + \frac{y ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = 5

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 6, b = 5

9 x^{2} - 16 y^{2} = 144

x^{2} + y^{2} + 6 x - 4 y = 0

f (x) = x^{2} + 2 x + 1

y^{2} = 28 x

3 x^{2} - 3 y = 0

What is (x^2)/(36)+(y^2)/(25)=1 ?
The solution to (x^2)/(36)+(y^2)/(25)=1 is Ellipse with (h,k)=(0,0),a=6,b=5