What is 1/4 y^2-y+x+1=0 ?

The solution to 1/4 y^2-y+x+1=0 is Parabola with (h,k)=(0,2),p=-1

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1/4 y^2-y+x+1=0

\frac{1}{4} y^{2} - y + x + 1 = 0

(h, k) = (0, 2), p = - 1

Solution steps

\frac{1}{4} y^{2} - y + x + 1 = 0

Rewrite

\frac{1}{4} y^{2} - y + x + 1 = 0

in the standard form

4 (- 1) (x - 0) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (0, 2), p = - 1

y^{2} + 4 y + 4 x + 8 = 0

e^{l n (y)} = e^{2 \cdot l n (x)}

x = 1 - (y + 2)^{2}

\frac{s ^{2} - 2 p + 6 p}{( s + 2 )} = 1

f, f (x)^{- 1} (x) = \frac{0.75}{10 - x}

What is 1/4 y^2-y+x+1=0 ?
The solution to 1/4 y^2-y+x+1=0 is Parabola with (h,k)=(0,2),p=-1