What is the foci 9x^2-4y^2-72x=0 ?

The foci 9x^2-4y^2-72x=0 is (4+2sqrt(13),0),(4-2sqrt(13),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 9x^2-4y^2-72x=0

foci

9 x^{2} - 4 y^{2} - 72 x = 0

(4 + 213, 0), (4 - 213, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

9 x^{2} - 4 y^{2} - 72 x = 0 :

Right-left Hyperbola with

(h, k) = (4, 0), a = 4, b = 6

(4 + c, 0), (4 - c, 0)

Compute

c :

c = 4^{2} + 6^{2} : 213

(4 + 213, 0), (4 - 213, 0)

f (x) = 2 x^{2} - x - 6

x^{2} - 4 y = 0

y^{2} = 4 x

3 x^{2} + 12 x + 4 y^{2} - 40 y + 100 = 0

(x + 2)^{2} + (y - 4)^{2} = 25

What is the foci 9x^2-4y^2-72x=0 ?
The foci 9x^2-4y^2-72x=0 is (4+2sqrt(13),0),(4-2sqrt(13),0)