What is the foci y^2+8x-6y=-25 ?

The foci y^2+8x-6y=-25 is (-4,3)

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foci y^2+8x-6y=-25

foci

y^{2} + 8 x - 6 y = - 25

(- 4, 3)

Solution steps

Rewrite

y^{2} + 8 x - 6 y = - 25

in the standard form

4 (- 2) (x - (- 2)) = (y - 3)^{2}

(h, k) = (- 2, 3), p = - 2

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(- 2, 3)

along the x-axis

(- 2 + p, 3)

= (- 2 + (- 2), 3)

Refine

(- 4, 3)

2 x^{2} - 19 x + 9

(x + 5)^{2} = - 20 (y - 2)

x^{2} + 6 x - 8 y + 1 = 0

y = x^{2} + 1

290 (8 x + 0.5 x^{2} - 1.4)