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Popular >

foci y^2+16x=0

Solution

foci

y^{2} + 16 x = 0

Solution

(- 4, 0)

Solution steps

Rewrite

y^{2} + 16 x = 0

in the standard form:

4 (- 4) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 4

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + (- 4), 0)

Refine

(- 4, 0)

Popular Examples

foci y=16-x^2 foci

y = 16 - x^{2}

foci y=196x^2-112x-240 foci

y = 196 x^{2} - 112 x - 240

foci y=+x^2-2x-3 foci

y = + x^{2} - 2 x - 3

foci y=x^2-5x3 foci

y = x^{2} - 5 x 3

foci x^2-3x+4 foci

x^{2} - 3 x + 4

Frequently Asked Questions (FAQ)

What is the foci y^2+16x=0 ?
The foci y^2+16x=0 is (-4,0)