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Popular >

foci 5x^2

Solution

foci

5 x^{2}

Solution

(0, \frac{1}{20})

Solution steps

Rewrite

y = 5 x^{2}

in the standard form:

4 \cdot \frac{1}{20} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{20}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + \frac{1}{20})

Refine

(0, \frac{1}{20})

Popular Examples

foci y=x^2-x+1 foci

y = x^{2} - x + 1

foci (x+3/5)(x-2/5)foci

(x + \frac{3}{5}) (x - \frac{2}{5})

foci+(y^3-100y)/(y+10)foci

+ \frac{y ^{3} - 100 y}{y + 10}

foci x^2-10x-24y=-25-24 foci

x^{2} - 10 x - 24 y = - 25 - 24

foci x^2=8(y-2)foci

x^{2} = 8 (y - 2)

Frequently Asked Questions (FAQ)

What is the foci 5x^2 ?
The foci 5x^2 is (0, 1/20)