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Popular >

foci y=x^2-x+1

Solution

foci

y = x^{2} - x + 1

Solution

(\frac{1}{2}, 1)

Solution steps

Rewrite

y = x^{2} - x + 1

in the standard form

4 \cdot \frac{1}{4} (y - \frac{3}{4}) = (x - \frac{1}{2})^{2}

(h, k) = (\frac{1}{2}, \frac{3}{4}), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{1}{2}, \frac{3}{4})

along the y-axis

(\frac{1}{2}, \frac{3}{4} + p)

= (\frac{1}{2}, \frac{3}{4} + \frac{1}{4})

Refine

(\frac{1}{2}, 1)

Popular Examples

foci (x+3/5)(x-2/5)foci

(x + \frac{3}{5}) (x - \frac{2}{5})

foci+(y^3-100y)/(y+10)foci

+ \frac{y ^{3} - 100 y}{y + 10}

foci x^2-10x-24y=-25-24 foci

x^{2} - 10 x - 24 y = - 25 - 24

foci x^2=8(y-2)foci

x^{2} = 8 (y - 2)

foci x^2-2x+5 foci

x^{2} - 2 x + 5

Frequently Asked Questions (FAQ)

What is the foci y=x^2-x+1 ?
The foci y=x^2-x+1 is (1/2 ,1)