What is the foci y=-0.0000848x^2-0.006005x+1.004 ?

The foci y=-0.0000848x^2-0.006005x+1.004 is (-35.40683…,-2948.11320…)

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foci y=-0.0000848x^2-0.006005x+1.004

foci

y = - 0.0000848 x^{2} - 0.006005 x + 1.004

(- 35.40683 \dots, - 2948.11320 \dots)

Solution steps

Rewrite

y = - 0.0000848 x^{2} - 0.006005 x + 1.004

in the standard form

4 (- 2948.11320 \dots) (y - 0) = (x - (- \frac{0.006005}{0.0001696}))^{2}

(h, k) = (- \frac{0.006005}{0.0001696}, 0), p = - 2948.11320 \dots

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{0.006005}{0.0001696}, 0)

along the y-axis

(- \frac{0.006005}{0.0001696}, 0 + p)

= (- \frac{0.006005}{0.0001696}, 0 + (- 2948.11320 \dots))

Refine

(- 35.40683 \dots, - 2948.11320 \dots)

y^{2} - \frac{3}{4} x = 0

40 x - 5 x^{2}

x = - \frac{3}{8} (y - 2)^{2} - 1

y = 3 x^{2} - 7

y = p (x - h)^{2} + k

What is the foci y=-0.0000848x^2-0.006005x+1.004 ?
The foci y=-0.0000848x^2-0.006005x+1.004 is (-35.40683…,-2948.11320…)