What is the foci (y^2)/(36)-(x^2)/(64)=1 ?

The foci (y^2)/(36)-(x^2)/(64)=1 is (0,10),(0,-10)

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foci (y^2)/(36)-(x^2)/(64)=1

foci

\frac{y ^{2}}{36} - \frac{x ^{2}}{64} = 1

(0, 10), (0, - 10)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{36} - \frac{x ^{2}}{64} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 6, b = 8

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 6^{2} + 8^{2} : 10

(0, 0 + 10), (0, 0 - 10)

Refine

(0, 10), (0, - 10)

x = y - y^{2}

y^{2} - 8 x = 0

x^{2} - 2 x + y^{2} + 2 y = 7

\frac{y ^{2}}{49} - \frac{x ^{2}}{64} = 1

y, 36 x^{2} - 25 y^{2} + 144 x - 50 y + 119 = 0

What is the foci (y^2)/(36)-(x^2)/(64)=1 ?
The foci (y^2)/(36)-(x^2)/(64)=1 is (0,10),(0,-10)