What is the foci (y^2)/(49)-(x^2)/(64)=1 ?

The foci (y^2)/(49)-(x^2)/(64)=1 is (0,sqrt(113)),(0,-sqrt(113))

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foci (y^2)/(49)-(x^2)/(64)=1

foci

\frac{y ^{2}}{49} - \frac{x ^{2}}{64} = 1

(0, 113), (0, - 113)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{49} - \frac{x ^{2}}{64} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 7, b = 8

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 7^{2} + 8^{2} : 113

(0, 0 + 113), (0, 0 - 113)

Refine

(0, 113), (0, - 113)

y, 36 x^{2} - 25 y^{2} + 144 x - 50 y + 119 = 0

\frac{x ^{2}}{100} - \frac{y ^{2}}{64} = 1

x^{2} + y^{2} \leq 4

f (x) = x^{2} + 4 x + 3

y = \frac{1}{12} x^{2}

What is the foci (y^2)/(49)-(x^2)/(64)=1 ?
The foci (y^2)/(49)-(x^2)/(64)=1 is (0,sqrt(113)),(0,-sqrt(113))