What is the directrix y^2-12y-4x+28=0 ?

The directrix y^2-12y-4x+28=0 is x=-3

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directrix y^2-12y-4x+28=0

directrix

y^{2} - 12 y - 4 x + 28 = 0

x = - 3

Solution steps

Rewrite

y^{2} - 12 y - 4 x + 28 = 0

in the standard form

4 \cdot 1 \cdot (x - (- 2)) = (y - 6)^{2}

(h, k) = (- 2, 6), p = 1

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 2, 6)

x-coordinate

x = - 2 - p

x = - 2 - 1

Refine

x = - 3

\frac{6 x}{7} \cdot \frac{4 x}{3}

9 y^{2} - 6 y - 9 - x = 0

2 X^{2}

x^{2} + 3 x - 4

y = x^{2} - 4 x + 4