What is the directrix y=4x+4x-2+x^2-3 ?

The directrix y=4x+4x-2+x^2-3 is y=-85/4

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directrix y=4x+4x-2+x^2-3

directrix

y = 4 x + 4 x - 2 + x^{2} - 3

y = - \frac{85}{4}

Solution steps

Rewrite

y = 4 x + 4 x - 2 + x^{2} - 3

in the standard form

4 \cdot \frac{1}{4} (y - (- 21)) = (x - (- 4))^{2}

(h, k) = (- 4, - 21), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 4, - 21)

y-coordinate

y = - 21 - p

y = - 21 - \frac{1}{4}

Refine

y = - \frac{85}{4}

y = - 5 x^{2} + 118 x + 7

- x^{2}

x = - 8 y^{2}

y = 4 x^{2} + 23 x - 6

4 - X^{2}

What is the directrix y=4x+4x-2+x^2-3 ?
The directrix y=4x+4x-2+x^2-3 is y=-85/4