What is the directrix x^2=28y ?

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directrix x^2=28y

directrix

x^{2} = 28 y

y = - 7

Solution steps

Rewrite

x^{2} = 28 y

in the standard form:

4 \cdot 7 (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = 7

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - 7

Refine

y = - 7

y = (3 x - 4) (4 x - 3) - 2 x

y = x^{2} + 4 x + 4

y = - x^{2} + 5

y = - x^{2} + 10 x

y = x^{2} + 3