What is the directrix x^2-16 ?

The directrix x^2-16 is y=-65/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

directrix x^2-16

directrix

x^{2} - 16

y = - \frac{65}{4}

Solution steps

Rewrite

y = x^{2} - 16

in the standard form:

4 \cdot \frac{1}{4} (y - (- 16)) = (x - 0)^{2}

(h, k) = (0, - 16), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, - 16)

y-coordinate

y = - 16 - p

y = - 16 - \frac{1}{4}

Refine

y = - \frac{65}{4}

- 0.0001 x^{2} + 6.4 x + 7600

x^{2} = 6 y

x = 3 y^{2}

y = x^{2} + 4 x - 1

y^{2} - 10 y - 12 x + 37 = 0