What is the directrix y=x^2-8 ?

The directrix y=x^2-8 is y=-33/4

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directrix y=x^2-8

directrix

y = x^{2} - 8

y = - \frac{33}{4}

Solution steps

Rewrite

y = x^{2} - 8

in the standard form:

4 \cdot \frac{1}{4} (y - (- 8)) = (x - 0)^{2}

(h, k) = (0, - 8), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, - 8)

y-coordinate

y = - 8 - p

y = - 8 - \frac{1}{4}

Refine

y = - \frac{33}{4}

- 0.4 x^{2} - 5

x + 5 + (y - 3)^{2} = 0

(x + 2)^{2} = 8 (y - 3)

\frac{x ^{4} - x ^{2} - 2 x - 1}{x ^{2} - x - 1}

y = 16 x^{2} + 1