What is the directrix (x+2)^2=8(y-3) ?

The directrix (x+2)^2=8(y-3) is y=1

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directrix (x+2)^2=8(y-3)

directrix

(x + 2)^{2} = 8 (y - 3)

y = 1

Solution steps

Rewrite

(x + 2)^{2} = 8 (y - 3)

in the standard form:

4 \cdot 2 (y - 3) = (x - (- 2))^{2}

(h, k) = (- 2, 3), p = 2

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 2, 3)

y-coordinate

y = 3 - p

y = 3 - 2

Refine

y = 1

\frac{x ^{4} - x ^{2} - 2 x - 1}{x ^{2} - x - 1}

y = 16 x^{2} + 1

y = 2 x^{2} + 7 x + 3

y = \frac{6 x}{7} \frac{4 x}{3}

\frac{4 x ^{3} + 11 x ^{2} + 4 x + 21}{x + 3}