What is the directrix y=16x^2+1 ?

The directrix y=16x^2+1 is y= 63/64

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directrix y=16x^2+1

directrix

y = 16 x^{2} + 1

y = \frac{63}{64}

Solution steps

Rewrite

y = 16 x^{2} + 1

in the standard form:

4 \cdot \frac{1}{64} (y - 1) = (x - 0)^{2}

(h, k) = (0, 1), p = \frac{1}{64}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 1)

y-coordinate

y = 1 - p

y = 1 - \frac{1}{64}

Refine

y = \frac{63}{64}

y = 2 x^{2} + 7 x + 3

y = \frac{6 x}{7} \frac{4 x}{3}

\frac{4 x ^{3} + 11 x ^{2} + 4 x + 21}{x + 3}

- \frac{1}{3} (x - 3) = (y + 5)^{2}

+ 2.5 t^{2} + 6 t