What is the directrix x= 1/12 y^2 ?

The directrix x= 1/12 y^2 is x=-3

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directrix x= 1/12 y^2

directrix

x = \frac{1}{12} y^{2}

x = - 3

Solution steps

Rewrite

x = \frac{1}{12} y^{2}

in the standard form:

4 \cdot 3 (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 3

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - 3

Refine

x = - 3

x = - 4 (y - 7)^{2} + 7

2 y^{2} - 16 x = 0

(x + 2)^{2} - 4

y = \frac{1}{4} (x + 5)^{2} - 1

y = + (x + 6)^{2}