What is the directrix+x^2-6x-7 ?

The directrix+x^2-6x-7 is y=-65/4

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directrix+x^2-6x-7

directrix

+ x^{2} - 6 x - 7

y = - \frac{65}{4}

Solution steps

Rewrite

y = x^{2} - 6 x - 7

in the standard form

4 \cdot \frac{1}{4} (y - (- 16)) = (x - 3)^{2}

(h, k) = (3, - 16), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(3, - 16)

y-coordinate

y = - 16 - p

y = - 16 - \frac{1}{4}

Refine

y = - \frac{65}{4}

lo g_{10} (6) x^{2}

y = \frac{1}{14} x^{2} + 2

x^{2} - 4 x + 4

6 x^{2} + 12 x

3 x^{2} + 18