What is the directrix y^2+12x-2y-11=0 ?

The directrix y^2+12x-2y-11=0 is x=4

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directrix y^2+12x-2y-11=0

directrix

y^{2} + 12 x - 2 y - 11 = 0

x = 4

Solution steps

Rewrite

y^{2} + 12 x - 2 y - 11 = 0

in the standard form

4 (- 3) (x - 1) = (y - 1)^{2}

(h, k) = (1, 1), p = - 3

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(1, 1)

x-coordinate

x = 1 - p

x = 1 - (- 3)

Refine

x = 4

\frac{x ^{2}}{9}

x^{2} + 36

y^{2} - 12 x - 2 y - 25 = 0

y = \frac{1}{4} (x - 1)^{2} - 2

25 x^{2} - 10 x - 200 y - 119 = 0