What is the directrix x=(y-3)^2+2 ?

The directrix x=(y-3)^2+2 is x= 7/4

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directrix x=(y-3)^2+2

directrix

x = (y - 3)^{2} + 2

x = \frac{7}{4}

Solution steps

Rewrite

x = (y - 3)^{2} + 2

in the standard form:

4 \cdot \frac{1}{4} (x - 2) = (y - 3)^{2}

(h, k) = (2, 3), p = \frac{1}{4}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(2, 3)

x-coordinate

x = 2 - p

x = 2 - \frac{1}{4}

Refine

x = \frac{7}{4}

14 x^{2}

y = \frac{- 4 x ^{2} + 24 x + 161}{25}

x^{2} - 12 x + 35

x = (2 y + 5)^{2}

6 x^{2} - 12 x