What is the directrix 5x^2+7 ?

The directrix 5x^2+7 is y= 139/20

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directrix 5x^2+7

directrix

5 x^{2} + 7

y = \frac{139}{20}

Solution steps

Rewrite

y = 5 x^{2} + 7

in the standard form:

4 \cdot \frac{1}{20} (y - 7) = (x - 0)^{2}

(h, k) = (0, 7), p = \frac{1}{20}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 7)

y-coordinate

y = 7 - p

y = 7 - \frac{1}{20}

Refine

y = \frac{139}{20}

(x + 1)^{2} = - 12 (y - 6)

4 x^{2} - 12 x - 2

3 x^{2} + 4 x - 3

y = 600 - 10 x + 0.25 x^{2}

11 x^{2} + 13