What is x^2+y^2+6x-4y+3=0 ?

The solution to x^2+y^2+6x-4y+3=0 is Circle with (a,b)=(-3,2),r=sqrt(10)

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x^2+y^2+6x-4y+3=0

x^{2} + y^{2} + 6 x - 4 y + 3 = 0

(a, b) = (- 3, 2), r = 10

Solution steps

x^{2} + y^{2} + 6 x - 4 y + 3 = 0

Rewrite

x^{2} + y^{2} + 6 x - 4 y + 3 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 2)^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 2), r = 10

f (x) = 3 x^{2} - 12 x + 8

x^{2} + y^{2} + 4 x - 2 y = - 1

\frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1

9 x^{2} + 16 y^{2} - 144 = 0

x^{2} + y^{2} = 49

What is x^2+y^2+6x-4y+3=0 ?
The solution to x^2+y^2+6x-4y+3=0 is Circle with (a,b)=(-3,2),r=sqrt(10)