What is x^2+y^2+4x-2y=-1 ?

The solution to x^2+y^2+4x-2y=-1 is Circle with (a,b)=(-2,1),r=2

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x^2+y^2+4x-2y=-1

x^{2} + y^{2} + 4 x - 2 y = - 1

(a, b) = (- 2, 1), r = 2

Solution steps

x^{2} + y^{2} + 4 x - 2 y = - 1

Rewrite

x^{2} + y^{2} + 4 x - 2 y = - 1

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 1)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 2, 1), r = 2

\frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1

9 x^{2} + 16 y^{2} - 144 = 0

x^{2} + y^{2} = 49

f (x) = x^{2} - 1

36 x^{2} + 36 y^{2} - 12 x - 27 y - 8 = 0

What is x^2+y^2+4x-2y=-1 ?
The solution to x^2+y^2+4x-2y=-1 is Circle with (a,b)=(-2,1),r=2