What is the directrix y^2-8x+2y+25=0 ?

The directrix y^2-8x+2y+25=0 is x=1

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directrix y^2-8x+2y+25=0

directrix

y^{2} - 8 x + 2 y + 25 = 0

x = 1

Solution steps

Rewrite

y^{2} - 8 x + 2 y + 25 = 0

in the standard form

4 \cdot 2 (x - 3) = (y - (- 1))^{2}

(h, k) = (3, - 1), p = 2

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(3, - 1)

x-coordinate

x = 3 - p

x = 3 - 2

Refine

x = 1

(x - 80)^{2} = - 320 (y - 20)

y = x^{2} + 7 x + 5

y = - 10 x^{2}

\frac{1}{8} x^{2} - y = 0

y = - 2 x^{2} - 3