What is the axis y-2=(x-1)^2 ?

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axis y-2=(x-1)^2

axis

y - 2 = (x - 1)^{2}

x = 1

Solution steps

y - 2 = (x - 1)^{2}

Rewrite

y - 2 = (x - 1)^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - 2) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 2), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 1

y = \frac{x ^{2} x ^{1}}{x}

y = x^{2} + 3

y = 3 x^{2}

y = 2 x (x - 9) - (x - 9)

y = x^{2} + 3 x - 70