What is the axis y=x^2+3 ?

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axis y=x^2+3

axis

y = x^{2} + 3

x = 0

Solution steps

y = x^{2} + 3

Rewrite

y = x^{2} + 3

in the standard form:

4 \cdot \frac{1}{4} (y - 3) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 3), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 3 x^{2}

y = 2 x (x - 9) - (x - 9)

y = x^{2} + 3 x - 70

y = (7 x - 3)^{2}

(x - h)^{2} = 4 p (y - k)