What is the axis y=2x(x-9)-(x-9) ?

The axis y=2x(x-9)-(x-9) is x= 19/4

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axis y=2x(x-9)-(x-9)

axis

y = 2 x (x - 9) - (x - 9)

x = \frac{19}{4}

Solution steps

y = 2 x (x - 9) - (x - 9)

Rewrite

y = 2 x (x - 9) - (x - 9)

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{289}{8})) = (x - \frac{19}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{19}{4}, - \frac{289}{8}), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{19}{4}

y = x^{2} + 3 x - 70

y = (7 x - 3)^{2}

(x - h)^{2} = 4 p (y - k)

y = x^{2} - x - 6

y^{2} - 10 y - 12 x + 37 = 0