What is the axis y=7x^2-10x+5 ?

The axis y=7x^2-10x+5 is x= 5/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=7x^2-10x+5

axis

y = 7 x^{2} - 10 x + 5

x = \frac{5}{7}

Solution steps

y = 7 x^{2} - 10 x + 5

Rewrite

y = 7 x^{2} - 10 x + 5

in the standard form

4 \cdot \frac{1}{28} (y - \frac{10}{7}) = (x - \frac{5}{7})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{7}, \frac{10}{7}), p = \frac{1}{28}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{5}{7}

y = - \frac{1}{2} x^{2} - 4 x + 10

y = x^{2} - x - 20

x^{2} + y = 5

y = x^{2} + 2 x - 1 - (2 x^{2} - 3 x + 6)

y = 1 - x^{2}