What is the axis 10y^2=22x ?

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axis 10y^2=22x

axis

10 y^{2} = 22 x

y = 0

Solution steps

10 y^{2} = 22 x

Rewrite

10 y^{2} = 22 x

in the standard form:

4 \cdot \frac{11}{20} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{11}{20}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = 4 x^{2} - 16 x + 11

y = 3 x - 3 x^{2}

y = + (x - 3)^{2} + 24

y = - x^{2} + 5 x - 2

y = x^{2} - 4