What is the axis y^2=-16x ?

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axis y^2=-16x

axis

y^{2} = - 16 x

y = 0

Solution steps

y^{2} = - 16 x

Rewrite

y^{2} = - 16 x

in the standard form:

4 (- 4) (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - 4

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = x^{2} + 8 x + 18

y = - 3 x^{2} + 5 x

y = x^{2} - 5 x - 14

y = 8 x^{2} + 12 x + 3

y = 4 x^{2} - 8 x + 7