What is the axis y=-3x^2+5x ?

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axis y=-3x^2+5x

axis

y = - 3 x^{2} + 5 x

x = \frac{5}{6}

Solution steps

y = - 3 x^{2} + 5 x

Rewrite

y = - 3 x^{2} + 5 x

in the standard form

4 (- \frac{1}{12}) (y - \frac{25}{12}) = (x - \frac{5}{6})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{6}, \frac{25}{12}), p = - \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{5}{6}

y = x^{2} - 5 x - 14

y = 8 x^{2} + 12 x + 3

y = 4 x^{2} - 8 x + 7

x^{2} = - 6 y

+ 5 x^{2} + 30 x + 24 y = 51