What is the axis y^2=16x ?

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axis y^2=16x

axis

y^{2} = 16 x

y = 0

Solution steps

y^{2} = 16 x

Rewrite

y^{2} = 16 x

in the standard form:

4 \cdot 4 (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 4

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

4 x^{2} - 20 x - 24 y + 97 = 0

y = x^{2} + 3 x - 4

y = 2 x^{2} - 2

y = x^{2} - 13 x + 40

y = x^{2} + 2 x - 15