What is the axis y=x^2+2x-15 ?

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axis y=x^2+2x-15

axis

y = x^{2} + 2 x - 15

x = - 1

Solution steps

y = x^{2} + 2 x - 15

Rewrite

y = x^{2} + 2 x - 15

in the standard form

4 \cdot \frac{1}{4} (y - (- 16)) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 16), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 1

y = - \frac{( x + 3 ) ^{2}}{20} + 1

F = \frac{m v ^{2}}{r}

y^{2} = x - 3

y = 4 (x + 1)^{2} - 3

y = x^{2} + 8 x + 12