What is the axis y=2x^2-2 ?

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axis y=2x^2-2

axis

y = 2 x^{2} - 2

x = 0

Solution steps

y = 2 x^{2} - 2

Rewrite

y = 2 x^{2} - 2

in the standard form:

4 \cdot \frac{1}{8} (y - (- 2)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 2), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = x^{2} - 13 x + 40

y = x^{2} + 2 x - 15

y = - \frac{( x + 3 ) ^{2}}{20} + 1

F = \frac{m v ^{2}}{r}

y^{2} = x - 3