What is the axis y=-x^2-3 ?

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axis y=-x^2-3

axis

y = - x^{2} - 3

x = 0

Solution steps

y = - x^{2} - 3

Rewrite

y = - x^{2} - 3

in the standard form:

4 (- \frac{1}{4}) (y - (- 3)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 3), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 3 x^{2} - 12 x + 10

x^{2} + 6 y = 0

x^{2} - 2 x + 8 y + 9 = 0

y^{2} = - 8 x

y = 3 x^{2} - 12 x + 8