What is the axis y=3x^2-30x+77 ?

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axis y=3x^2-30x+77

axis

y = 3 x^{2} - 30 x + 77

x = 5

Solution steps

y = 3 x^{2} - 30 x + 77

Rewrite

y = 3 x^{2} - 30 x + 77

in the standard form

4 \cdot \frac{1}{12} (y - 2) = (x - 5)^{2}

Therefore parabola properties are:

(h, k) = (5, 2), p = \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 5

y = x^{2} - 7

y^{2} = 32 x

y = + 14 - x^{2}

y = 2 x^{2} + 28 x + 105

y = 4 \cdot x^{2} - 3 \cdot x - 12