What is the axis y=2x^2+28x+105 ?

The axis y=2x^2+28x+105 is x=-7

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axis y=2x^2+28x+105

axis

y = 2 x^{2} + 28 x + 105

x = - 7

Solution steps

y = 2 x^{2} + 28 x + 105

Rewrite

y = 2 x^{2} + 28 x + 105

in the standard form

4 \cdot \frac{1}{8} (y - 7) = (x - (- 7))^{2}

Therefore parabola properties are:

(h, k) = (- 7, 7), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 7

y = 4 \cdot x^{2} - 3 \cdot x - 12

x \leq y^{2}

y = (2 X + 5) (3 X - 7)

f (x) = - x^{2} - 4 x + 5

x = y^{2} - 2 y