What is the axis y=4*x^2-3*x-12 ?

The axis y=4*x^2-3*x-12 is x= 3/8

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axis y=4x^2-3x-12

axis

y = 4 \cdot x^{2} - 3 \cdot x - 12

x = \frac{3}{8}

Solution steps

y = 4 x^{2} - 3 x - 12

Rewrite

y = 4 x^{2} - 3 x - 12

in the standard form

4 \cdot \frac{1}{16} (y - (- \frac{201}{16})) = (x - \frac{3}{8})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{8}, - \frac{201}{16}), p = \frac{1}{16}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{3}{8}

x \leq y^{2}

y = (2 X + 5) (3 X - 7)

f (x) = - x^{2} - 4 x + 5

x = y^{2} - 2 y

x = + (y + 3)^{2}