What is the axis x<= y^2 ?

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axis x<= y^2

axis

x \leq y^{2}

y = 0

Solution steps

x \leq y^{2}

Rewrite

x \leq y^{2}

in the standard form:

4 \cdot \frac{1}{4} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = (2 X + 5) (3 X - 7)

f (x) = - x^{2} - 4 x + 5

x = y^{2} - 2 y

x = + (y + 3)^{2}

y = x^{2} - 2 x^{1}