What is the axis y=11-x^2 ?

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axis y=11-x^2

axis

y = 11 - x^{2}

x = 0

Solution steps

y = 11 - x^{2}

Rewrite

y = 11 - x^{2}

in the standard form:

4 (- \frac{1}{4}) (y - 11) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 11), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = (x - 1) (x - 3)

x^{2} - 6 x + 8 y - 31 = 0

y = - 4 x^{2} - 8 x - 6

y = - 2 x^{2} - 2 x - 2

x^{2} = - 12 y