What is the axis y=-4x^2-8x-6 ?

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axis y=-4x^2-8x-6

axis

y = - 4 x^{2} - 8 x - 6

x = - 1

Solution steps

y = - 4 x^{2} - 8 x - 6

Rewrite

y = - 4 x^{2} - 8 x - 6

in the standard form

4 (- \frac{1}{16}) (y - (- 2)) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 2), p = - \frac{1}{16}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 1

y = - 2 x^{2} - 2 x - 2

x^{2} = - 12 y

3 x^{2} + 8 y = 0

y = 3 x^{2} + 9 x + 9

y = 0.07 x^{2} + 20 x + 350